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Trains, A and B are travelling on the same route heading towards the same destination. Train B has already covered a distance of 220 km before train A started. The two trains meet each other 11 hours after the start of train A. Had the trains been travelling towards each other (from a distance of 220 km), they would have met after one hour. What is the speed of train B in km/hr?
  • a)
    100
  • b)
    180
  • c)
    116
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Trains, A and B are travelling on the same route heading towards the s...
Let the speed of train A = x
and the speed of train B = y
⇒ Relative speed (same direction) = (x + y) kmph
and relative speed (opp. direction) = (x - y) kmph
⇒ 1(x - y) = 220] x 11
11(x + y) = 220
⇒ 11x - 11y = 2420 .....(1)
11x + 11y = 220 .....(2)
Solving equation (1) and (2) we get
22x = 2640
⇒ x = 120 kmph
⇒ y = 220 - 120 = 100 kmph
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Most Upvoted Answer
Trains, A and B are travelling on the same route heading towards the s...
Given information:
- Train B has covered 220 km before Train A started.
- The two trains meet each other 11 hours after the start of Train A.
- If the trains were travelling towards each other from a distance of 220 km, they would have met after one hour.

To find: The speed of Train B in km/hr.

Let's assume the speed of Train A and Train B as x and y km/hr respectively.

Calculations:
- When the two trains meet, the total distance covered by both trains is the same.
- Distance covered by Train B = 220 km (given)
- Distance covered by Train A = x * 11 (as Train A started 11 hours after Train B and they met after 11 hours)
- Total distance = Distance covered by Train A + Distance covered by Train B = 220 + 11x km
- Time taken by Train B to cover 220 km = 220/y hours
- When the trains travel towards each other, their relative speed = x + y km/hr
- They cover a distance of 220 km in 1 hour, so 220 = (x + y) * 1

Now, using the formula: Distance = Speed * Time
- Distance covered by Train A = x * 11 km
- Distance covered by Train B = y * (11 - 220/y) km (as Train B started earlier and covered 220 km before Train A started)
- Equating both distances:
x * 11 = y * (11 - 220/y)
x * 11 = 11y - 220
x = (11y - 220)/11 = y - 20

Substituting x in the total distance equation:
220 + 11x = 220 + 11(y - 20) = 11y - 100 km

Now, equating total distance with speed and time:
11y - 100 = (x + y) * 11
11y - 100 = (y + y - 20) * 11
11y - 100 = 22y - 220
11y = 120
y = 120/11 km/hr ≈ 10.91 km/hr

Therefore, the speed of Train B is 10.91 * 60 = 654.55 km/hr ≈ 100 km/hr (approx.)
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Trains, A and B are travelling on the same route heading towards the same destination. Train B has already covered a distance of 220 km before train A started. The two trains meet each other 11 hours after the start of train A. Had the trains been travelling towards each other (from a distance of 220 km), they would have met after one hour. What is the speed of train B in km/hr?a)100b)180c)116d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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