Find the mass of NaOH present in 250mL of semiNormality solution? (a) 3 (b) 4 (c) 5 (d) 6?

Question

Answer

Solution:

Given,

Volume of the solution = 250 mL

Semi-normality of the solution = 0.5 N

We know that,

Normality (N) = Number of gram equivalents of solute / Volume of solution in liters

Semi-normality is half of normality. Therefore,

0.5 N = (Number of gram equivalents of solute) / (0.25 L)

Number of gram equivalents of solute = 0.125N

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Gram equivalent weight of NaOH = Molar mass / Basicity

Basicity of NaOH is 1.

Therefore,

Gram equivalent weight of NaOH = 40 g/mol

Now, we can calculate the mass of NaOH present in 250 mL of the solution as follows:

Mass of NaOH = (Number of gram equivalents of NaOH) x (Gram equivalent weight of NaOH)

= 0.125N x 40 g/mol

= 5 g

Therefore, the mass of NaOH present in 250 mL of 0.5 N NaOH solution is 5 g.

Hence, the correct answer is option (c) 5.

Answer

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