1)What mass of methanol (CH3OH) must be added to 2.5 mole of ethanol(C2H5OH)in order to produce a solution containing equal numbers of molecules of two species (2) Assuming no. Of chemical reaction occurs what is the total number of molecules present in resulting solution??? ?

Question

Answer

Problem Statement

What mass of methanol (CH3OH) must be added to 2.5 mole of ethanol(C2H5OH)in order to produce a solution containing equal numbers of molecules of two species? Assuming no chemical reaction occurs, what is the total number of molecules present in the resulting solution?

Solution

Calculating Number of Molecules

The first step is to calculate the number of molecules present in the initial solution of 2.5 moles of ethanol. This can be done using Avogadro's number, which states that one mole of any substance contains 6.02 x 10^23 molecules.

Therefore, the total number of molecules in 2.5 moles of ethanol is:

2.5 moles x 6.02 x 10^23 molecules/mole = 1.505 x 10^24 molecules

Calculating Required Number of Molecules

Since we want a solution containing equal numbers of molecules of two species, we need to add an equal number of molecules of methanol to the solution. Therefore, the total number of molecules in the resulting solution should be twice the number of molecules in the initial solution.

2 x 1.505 x 10^24 molecules = 3.01 x 10^24 molecules

Calculating Mass of Methanol Required

Next, we need to calculate the mass of methanol required to achieve the desired number of molecules in the resulting solution. This can be done using the formula:

moles = mass / molar mass

First, we need to calculate the number of moles of methanol required to achieve the desired number of molecules:

moles of methanol = 3.01 x 10^24 molecules / 6.02 x 10^23 molecules/mole = 5 moles

Now, we can use the known molar mass of methanol (32.04 g/mol) to calculate the mass of methanol required:

mass of methanol = 5 moles x 32.04 g/mol = 160.2 g

Conclusion

In conclusion, 160.2 g of methanol must be added to 2.5 moles of ethanol in order to produce a solution containing equal numbers of molecules of two species. The total number of molecules in the resulting solution is 3.01 x 10^24 molecules.

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