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what is the molality of the solution prepared by dissolving 125ml of pure methanol (d=0.8mL) in 375g of ethanol.
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Calculating Molality of Solution

To calculate the molality of the solution, we need to first find the number of moles of methanol present in the solution. We can use the formula:

n = m/M

where n is the number of moles, m is the mass of the substance, and M is the molar mass of the substance.

Find the number of moles of methanol

- Mass of methanol = Volume x Density = 125 mL x 0.8 g/mL = 100 g
- Molar mass of methanol = 32 g/mol
- Number of moles of methanol = 100 g / 32 g/mol = 3.125 mol

Find the total mass of the solution

- Mass of ethanol = 375 g
- Total mass of solution = Mass of methanol + Mass of ethanol = 100 g + 375 g = 475 g

Calculate Molality

- Molality = moles of solute / mass of solvent in Kg
- Mass of solvent = Mass of ethanol / 1000 = 375 g / 1000 = 0.375 kg
- Molality = 3.125 mol / 0.375 kg = 8.33 mol/kg

Therefore, the molality of the solution prepared by dissolving 125 mL of pure methanol in 375 g of ethanol is 8.33 mol/kg.
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what is the molality of the solution prepared by dissolving 125ml of pure methanol (d=0.8mL) in 375g of ethanol. Related: NCERT Solutions - Solutions (Part - 1)?
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