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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48?
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Divide 56 into two parts such that three times the first part exceeds ...
**Problem Analysis**

Let's assume the two parts of 56 are x and 56 - x.

According to the problem, three times the first part (3x) exceeds one third of the second part ((56 - x)/3) by 48.

Mathematically, this can be represented as:

3x = (56 - x)/3 + 48

Simplifying the equation, we have:

9x = 56 - x + 144

10x = 200

x = 20

Therefore, the two parts of 56 are 20 and 36.

**Solution**

Based on the analysis above, the two parts of 56 are 20 and 36.

Let's verify this solution by substituting the values into the equation:

3x = (56 - x)/3 + 48

3(20) = (56 - 20)/3 + 48

60 = 36/3 + 48

60 = 12 + 48

60 = 60

The equation holds true, confirming that the solution is correct.

Therefore, the two parts of 56 are 20 and 36.

**Conclusion**

To divide 56 into two parts such that three times the first part exceeds one third of the second part by 48, we find that the two parts are 20 and 36.
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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48?
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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Divide 56 into two parts such that three times the first part exceeds one third of the second by 48? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Divide 56 into two parts such that three times the first part exceeds one third of the second by 48?.
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