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Consider the following dissociation of O2 (dissociation energy 498 kJ mol -1) is more energetic than normal oxygen atom (O) by 1.967 eV. Thus, maximum wavelength for photochemical dissociation isa)174 nmb)398 nmc)174 pmd)398 pmCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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Consider the following dissociation of O2 (dissociation energy 498 kJ mol -1) is more energetic than normal oxygen atom (O) by 1.967 eV. Thus, maximum wavelength for photochemical dissociation isa)174 nmb)398 nmc)174 pmd)398 pmCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Consider the following dissociation of O2 (dissociation energy 498 kJ mol -1) is more energetic than normal oxygen atom (O) by 1.967 eV. Thus, maximum wavelength for photochemical dissociation isa)174 nmb)398 nmc)174 pmd)398 pmCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Consider the following dissociation of O2 (dissociation energy 498 kJ mol -1) is more energetic than normal oxygen atom (O) by 1.967 eV. Thus, maximum wavelength for photochemical dissociation isa)174 nmb)398 nmc)174 pmd)398 pmCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider the following dissociation of O2 (dissociation energy 498 kJ mol -1) is more energetic than normal oxygen atom (O) by 1.967 eV. Thus, maximum wavelength for photochemical dissociation isa)174 nmb)398 nmc)174 pmd)398 pmCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.