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A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm–3, then the number of atoms present in 256g of the crystal is N × 1024. The value of N is
  • a)
    2
  • b)
    4
  • c)
    6
  • d)
    8
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A crystalline solid of a pure substance has a face-centred cubic struc...
Formula of density = 
For FCC unit cell Z = 4
Edge length a = 4 * 10-8 cm



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A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm–3, then the number of atoms present in 256g of the crystal is N × 1024. The value of N isa)2b)4c)6d)8Correct answer is option 'A'. Can you explain this answer?
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A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm–3, then the number of atoms present in 256g of the crystal is N × 1024. The value of N isa)2b)4c)6d)8Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm–3, then the number of atoms present in 256g of the crystal is N × 1024. The value of N isa)2b)4c)6d)8Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm–3, then the number of atoms present in 256g of the crystal is N × 1024. The value of N isa)2b)4c)6d)8Correct answer is option 'A'. Can you explain this answer?.
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