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X^1/p=y^1/q=z^1/r and xyz=1 ,then the value of p q r is?
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X^1/p=y^1/q=z^1/r and xyz=1 ,then the value of p q r is?
Explanation:
Given, X^1/p=y^1/q=z^1/r and xyz=1

We need to find the value of p, q, and r.


Solution:
Step 1: Express X, Y, and Z in terms of p, q, and r

As per the given equation,

X^1/p=y^1/q=z^1/r

Let's take the cube of all the terms,

X^3/p=y^3/q=z^3/r

Now, let's express X, Y, and Z in terms of p, q, and r

X = (X^3/p)^(1/3) = (Y^3/q)^(1/3) = (Z^3/r)^(1/3)

Y = (X^3/p)^(1/3) = (Y^3/q)^(1/3) = (Z^3/r)^(1/3)

Z = (X^3/p)^(1/3) = (Y^3/q)^(1/3) = (Z^3/r)^(1/3)


Step 2: Substitute the value of X, Y, and Z in xyz=1

xyz=1

(X*Y*Z) = 1

[(X^3/p)^(1/3)] * [(Y^3/q)^(1/3)] * [(Z^3/r)^(1/3)] = 1

[X^(3/p) * Y^(3/q) * Z^(3/r)]^(1/3) = 1

[X^(q*r) * Y^(p*r) * Z^(p*q)]^(1/3) = 1

X^(q*r) * Y^(p*r) * Z^(p*q) = 1


Step 3: Substitute the value of X, Y, and Z in X^3/p=y^3/q=z^3/r

X^3/p=y^3/q=z^3/r

Substituting the value of X, Y, and Z,

(X^(q*r))^3/p = (Y^(p*r))^3/q = (Z^(p*q))^3/r

X^(3q*r/p) = Y^(3p*r/q) = Z^(3p*q/r)


Step 4: Equate the exponents in the above two equations

X^(3q*r/p) = Y^(3p*r/q) = Z^(3p*q/r)

3q*r/p = 3p*r/q = 3p*q/r

q = 3p, r = 3q = 9p


Step 5: Find the value of p

q = 3p, r = 9p

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X^1/p=y^1/q=z^1/r and xyz=1 ,then the value of p q r is?
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X^1/p=y^1/q=z^1/r and xyz=1 ,then the value of p q r is?
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