Oxidation state of Fe in the complex K3[Fe(CN)5NO] is (+) __________.Correct answer is '1'. Can you explain this answer?

Question

Answer

The answer can't be +1. It should be +2.

Let x be the oxidation state of x

oxidation number of K ion = +1

oxidation number of CN ion = -1

oxidation number of NO = 0 [since it is a neutral ligand]

Therefore,

1(3) + x -1(5) + 0 = 0

⟹ 3 + x - 5 = 0

⟹ x -2 = 0

⟹ x = +2

Hope this helps you...!

Answer

K3[Fe(CN)5NO]
3(+1)+x+5(-1)+1 =0
3+x-5+1=0
x-1=0
x=+1
hence the oxidation number in K3[Fe(CN)5NO] is +1

Answer

Answer:

Oxidation State of Fe in K3[Fe(CN)5NO] is +1.

Explanation:

Oxidation state or oxidation number is defined as the charge that an atom appears to have when all other atoms are removed in ionizing the molecule or compound. In the given complex, we can find the oxidation state of Fe as follows.

Step 1: Identify the oxidation state of each ligand in the complex. Here, CN^- and NO are neutral ligands with oxidation state of -1 and 0, respectively.

Step 2: Assign an oxidation state x to Fe.

Step 3: Calculate the total oxidation state of the complex by adding the oxidation state of each ligand and the oxidation state of Fe, which must be equal to the charge of the complex (here, it is 3-).

K3[Fe(CN)5NO] can be written as K3[Fe(CN)5(NO)] since NO is a neutral ligand.

K3[Fe(CN)5(NO)] = +3 (K) + x (Fe) + 5(-1) (CN) + 0 (NO) = -3

Simplifying the above equation, we get:

x = +1

Therefore, the oxidation state of Fe in K3[Fe(CN)5NO] is +1.

Similar IIT JAM Doubts

Consider the following statements, the true statement(s) is/are

Oxidation state of Nitrogen in (NH4)2Cr2O7 ?

[Fe(CN)6No]2- hybridization Related: Valence Bond Theory - Chemical Bonding, Inorganic Chemistry?

What is oxidation state of nitrogen in HN3?

Is fluorine acts as strong field ligand in higher oxidation state . Is it true or not . Explain?

Top Courses for IIT JAM

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams