Two coins are tossed simultaneously. The probability of getting at mos...
Condition is at most 1 tail means no tail is also acceptable
so No of ways- 3 (T,H), (H,T), (H,H)
Total No of ways-2*2=4 (T,T), (H,H),(T,H), (H,T)
Probability=3/4 { thus Option C }
Two coins are tossed simultaneously. The probability of getting at mos...
Probability of getting at most one tail:
To find the probability of getting at most one tail when two coins are tossed simultaneously, we need to consider all the possible outcomes and determine the favorable outcomes.
Possible outcomes:
When two coins are tossed simultaneously, there are four possible outcomes:
1. Both coins land heads up (HH)
2. Coin 1 lands heads up and Coin 2 lands tails up (HT)
3. Coin 1 lands tails up and Coin 2 lands heads up (TH)
4. Both coins land tails up (TT)
Favorable outcomes:
We need to determine the favorable outcomes where there is at most one tail. Let's analyze each possible outcome:
1. Both coins land heads up (HH) - No tails, favorable outcome.
2. Coin 1 lands heads up and Coin 2 lands tails up (HT) - One tail, favorable outcome.
3. Coin 1 lands tails up and Coin 2 lands heads up (TH) - One tail, favorable outcome.
4. Both coins land tails up (TT) - Two tails, not a favorable outcome.
From the above analysis, we have three favorable outcomes: HH, HT, TH.
Probability calculation:
To determine the probability, we need to divide the number of favorable outcomes by the total number of possible outcomes.
Number of favorable outcomes = 3
Total number of possible outcomes = 4
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 3/4
Therefore, the probability of getting at most one tail when two coins are tossed simultaneously is 3/4, which corresponds to option 'C'.