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In a YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 nm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is -
  [JEE' 2004 (Scr)]
  • a)
    4 mm
  • b)
     5.6 mm
  • c)
    14 mm
  • d)
    28 mm
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In a YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used...
Let nth minima of 400 nm wave coincides with mth minima of 560 nm wave.
 
Then,
 
(2n-1)(400/2) - (2m-1)(560/2)
 
2n-1 /2m-1  = 7/5 =14/10 ....
That is, 4th minima of 400 nm wave coincides with 3rd minima of 560 nm wave.
Location of this minima is-
y1 =[ (2×4-1).(1000).(400×10-6 ) ] / 2×0.1           (given, d=0.1 )
= 14 mm
Next 11th minima of 400 nm wave will coincide with 8thminima of 560 nm wave.
Location of this second minima is-
y2 = [(2×11-1).(1000).(400×10-6 )] /2×0.1
= 42 mm
So, the distance  between two successive regions of complete darkness is,
y2 - y1 = 42-14 = 28 mm
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In a YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 nm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is - [JEE 2004 (Scr)]a)4 mmb)5.6 mmc)14 mmd)28 mmCorrect answer is option 'D'. Can you explain this answer?
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In a YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 nm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is - [JEE 2004 (Scr)]a)4 mmb)5.6 mmc)14 mmd)28 mmCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 nm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is - [JEE 2004 (Scr)]a)4 mmb)5.6 mmc)14 mmd)28 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a YDSE bi-chromatic light of wavelengths 400 nm and 560 nm are used. The distance between the slits is 0.1 nm and the distance between the plane of the slits and the screen is 1m. The minimum distance between two successive regions of complete darkness is - [JEE 2004 (Scr)]a)4 mmb)5.6 mmc)14 mmd)28 mmCorrect answer is option 'D'. Can you explain this answer?.
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