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In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solution
of sodium sulphite (Na2SO3) In the reaction SO3-2 is oxidised to SO4-2, if the original oxidation number
of metal in the salt was 3, what would be the new oxidation number of the metal?
  • a)
    2
  • b)
    0
  • c)
    1
  • d)
    4
Correct answer is option 'A'. Can you explain this answer?
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In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted e...
Given:
- Volume of 0.1 M solution of metallic salt = 50 ml
- Volume of 0.1 M solution of sodium sulphite (Na2SO3) = 25 ml

To find:
- The new oxidation number of the metal

Solution:
1. First, let's write the balanced chemical equation for the reaction between the metallic salt and sodium sulphite:

xM + Na2SO3 → Na2SO4 + yM

2. Since the original oxidation number of the metal in the salt was 3, we can assign it as x.
3. The oxidation state of sulfur in SO3^2- is +4, and in SO4^2- it is +6.
4. In order for the reaction to occur, the metal in the salt must undergo oxidation. This means that its oxidation number must increase from 3 to a higher value.
5. By comparing the oxidation states of sulfur in SO3^2- (+4) and SO4^2- (+6), we can conclude that the metal in the salt must have an oxidation state higher than +3.
6. Therefore, the new oxidation number of the metal must be +4.
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In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer?
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In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer?.
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