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In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer?, a detailed solution for In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In an experiment, 50 ml of 0.1 M solution of a metallic salt reacted exactly with 25 ml of 0.1 M solutionof sodium sulphite (Na2SO3) In the reaction SO3-2is oxidised to SO4-2, if the original oxidation numberof metal in the salt was 3, what would be the new oxidation number of the metal?a)2b)0c)1d)4Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.