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A thin circular ring of mass m and radius R is rotating about its axis with a constant angular velocity w. Two objects each of mass M are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity w' = 
[AIEEE 2006]
  • a)
     
  • b)
     
  • c)
     
  • d)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A thin circular ring of mass m and radius R is rotating about its axis...
The initial angular momentum of the ring will be:
Li​=mR2ω
whereas the final angular momentum is given as:
Lf​=mR2ωnew​+2MR2ωnew
Conserving angular momentum
mR2ω=(mR2+2MR2new​
⇒ωnew​=m​ω/m+2M
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A thin circular ring of mass m and radius R is rotating about its axis...
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Community Answer
A thin circular ring of mass m and radius R is rotating about its axis...
D is correct.
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A thin circular ring of mass m and radius R is rotating about its axis with a constant angular velocity w. Two objects each of mass M are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity w =[AIEEE 2006]a)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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