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When mercuric iodide is added to an aqueous solution 
of potassium iodide (in excess), a soluble complex, 
 is formed. Then, 
  • a)
    the freezing point of the resulting solution is raised 
  • b)
    the freezing point of the resulting solution is lowered 
  • c)
    the freezing point of the resulting solution does not 
    change 
     
  • d)
    the boiling point of the resulting does not change
Correct answer is option 'A'. Can you explain this answer?
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When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer?
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When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer?.
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