Question Description
When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
according to
the JEE exam syllabus. Information about When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer?.
Solutions for When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When mercuric iodide is added to an aqueous solutionof potassium iodide (in excess), a soluble complex,is formed. Then, a)the freezing point of the resulting solution is raisedb)the freezing point of the resulting solution is loweredc)the freezing point of the resulting solution does notchanged)the boiling point of the resulting does not changeCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.