a ray of light along x+√3y-√3=0 gets reflected upon reaching x- axis the eq of reflection???? help if anybody can??????

Question

Answer

you can also simply change sign of y-cordinte.......as it is reflectd by x-axis

Answer

ooohhh i got it thanks jaahnvi

Answer

To write the equation of line we need to find a point lying on it and it's slopeThe slope of given line is - 1/(3)^1/2So the slope of required line is (3)^1/2So by the formula (y-y') =m(x-x') (y-0)=(3)^1/2{x-(3)^1/2}y=(3)^1/2x-3Hope this helps

Answer

Slope of given line is - 1/(3)^1/2The slope of required line will be 1/(3)^1/2by the formula (y-y') =m(x-x'){(3)^1/2}y=x-(3)^1/2

Answer

Reflection of a Ray of Light along x+√3y-√3=0 on the x-axis

Given equation of the ray of light:
The equation of the ray of light is x+√3y-√3=0.

Reflection on the x-axis:
When the ray of light reaches the x-axis, it gets reflected. The reflection on the x-axis is such that the angle of incidence is equal to the angle of reflection.

Equation of the reflected ray:
To find the equation of the reflected ray, we need to determine the slope of the incident ray and then calculate the slope of the reflected ray using the angle of incidence and the normal to the reflecting surface (in this case, the x-axis).

Calculating the slope of the incident ray:
The given equation of the incident ray is x+√3y-√3=0. By rearranging the equation in the slope-intercept form y = mx + c, we find that the slope of the incident ray is -1/√3.

Calculating the slope of the reflected ray:
Since the angle of incidence is equal to the angle of reflection, the slope of the reflected ray will be the negative reciprocal of the slope of the incident ray. Therefore, the slope of the reflected ray will be √3.

Equation of the reflected ray:
Now that we have the slope of the reflected ray, we can find the equation of the reflected ray by considering the point of reflection on the x-axis. Let's assume the point of reflection is (a, 0). Using the slope-intercept form, the equation of the reflected ray will be y = √3(x-a).

Therefore, the equation of the reflected ray of light along x+√3y-√3=0 upon reaching the x-axis is y = √3(x-a), where 'a' is the x-coordinate of the point of reflection.

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