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Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor only. If the peak value of the current in the circuit is 1.57 A at t = 0. The expression for the instantaneous voltage across the capacitor will be
  • a)
     E = 50 sin (100 pt – p/2) 
  • b)
    E = 100 sin (50 pt)
  • c)
    E = 50 sin 100 pt
  • d)
    E = 50 sin (100 pt + p/2)
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor ...
Peak value of voltage
V0=i0XC =i0/2πvC
=>1.57/(2x3.14x50x100x10-6)
Hence if equation of current i = io sin ω t then in capacitive circuit voltage is 
V=V0 (ωt -  π/2)
=>50[sin2π x50t- (π/2)]
 =50[100πt-(π/2)]
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Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor ...
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Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor ...
The expression for the instantaneous voltage across the capacitor can be found using the formula for the voltage across a capacitor in an AC circuit:

V(t) = Vpeak * sin(ωt)

where V(t) is the instantaneous voltage across the capacitor at time t, Vpeak is the peak value of the voltage, ω is the angular frequency (2πf), and t is the time.

Given that f = 50 Hz, ω = 2πf = 2π(50) = 100π rad/s, and Vpeak = 1.57 A, the expression for the instantaneous voltage across the capacitor is:

V(t) = 1.57 * sin(100πt)

Therefore, the correct expression for the instantaneous voltage across the capacitor is:

E = 1.57 * sin(100πt)
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Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor only. If the peak value of the current in the circuit is 1.57 A at t = 0. The expression for the instantaneous voltage across the capacitor will bea)E = 50 sin (100 pt –p/2)b)E = 100 sin (50 pt)c)E = 50 sin 100 ptd)E = 50 sin (100 pt + p/2)Correct answer is option 'C'. Can you explain this answer?
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Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor only. If the peak value of the current in the circuit is 1.57 A at t = 0. The expression for the instantaneous voltage across the capacitor will bea)E = 50 sin (100 pt –p/2)b)E = 100 sin (50 pt)c)E = 50 sin 100 ptd)E = 50 sin (100 pt + p/2)Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor only. If the peak value of the current in the circuit is 1.57 A at t = 0. The expression for the instantaneous voltage across the capacitor will bea)E = 50 sin (100 pt –p/2)b)E = 100 sin (50 pt)c)E = 50 sin 100 ptd)E = 50 sin (100 pt + p/2)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let f = 50 Hz, and C = 100 mF in an AC circuit containing a capacitor only. If the peak value of the current in the circuit is 1.57 A at t = 0. The expression for the instantaneous voltage across the capacitor will bea)E = 50 sin (100 pt –p/2)b)E = 100 sin (50 pt)c)E = 50 sin 100 ptd)E = 50 sin (100 pt + p/2)Correct answer is option 'C'. Can you explain this answer?.
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