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The values of x in the equation 7(x+2p)2+5p2=35xp+117p2 are 
  • a)
    (4p, -3p) 
  • b)
    (4p, 3p) 
  • c)
    (-4p, 3p) 
  • d)
    (-4p, -3p) 
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The values of x in the equation 7(x+2p)2+5p2=35xp+117p2area)(4p, -3p)b...
Solution:

Given equation is 7(x -2p)² + 5p² = 35xp + 117p².

We are asked to find the values of x which satisfy this equation.

Step 1: Simplify the equation

7(x -2p)² = 35xp + 117p² - 5p²

7(x -2p)² = 35xp + 112p²

(x -2p)² = 5xp + 16p²

x² - 4xp + 4p² = 5xp + 16p²

x² - 9xp + 12p² = 0

Step 2: Factorize the equation

(x - 3p)(x - 4p) = 0

Step 3: Find the values of x

x - 3p = 0 or x - 4p = 0

x = 3p or x = 4p

Therefore, the values of x that satisfy the equation are x = 3p and x = 4p.

Answer: Option A (4p, -3p)
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Community Answer
The values of x in the equation 7(x+2p)2+5p2=35xp+117p2area)(4p, -3p)b...
7(x+2p)^2+5p^2=35p+117p^2
7(x^2+4p^2+4xp)+5p^2=35xp+117p^2
7x^2+28xp+28p^2+5p^2-35xp-117x^2=0
Simplifying,
7x^2-7x-84p^2=0
x^2-xp-12p^2=0
x^2-4xp+3xp-12p^2=0
x(x-4p)+3p(x-4p)=0
(x-4p)(x+3p)=0
x-4p=0 or x+3p=0
x=4p x=-3p
Therefore,The values of x are (4p,-3p)
Option A
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The values of x in the equation 7(x+2p)2+5p2=35xp+117p2area)(4p, -3p)b)(4p, 3p)c)(-4p, 3p)d)(-4p, -3p)Correct answer is option 'A'. Can you explain this answer?
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