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A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c?
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Given Data:
Molar ratio of methane to ethene = x:y
Average molecular mass = 20u
Calculation:
Let the molar mass of methane be 'a' and the molar mass of ethene be 'b'.
According to the given data:
(a*x + b*y)/(x+y) = 20
When the molar ratio is reversed (y:x), the new average molar mass will be:
(b*x + a*y)/(x+y)
Substitute the values:
From the given data, we know that:
a = 16u (molar mass of methane)
b = 28u (molar mass of ethene)
Substitute the values into the equation:
(28*x + 16*y)/(x+y)
Simplify the equation:
(28x + 16y)/(x+y) = (4(7x) + 4(4y))/(x+y) = 4(7x + 4y)/(x+y) = 4(20)/(x+y) = 80/(x+y)
Therefore, the mean molar mass when the molar ratio is y:x will be 80u/(x+y).
Final Answer:
The mean molar mass, when they are mixed in molar ratio of y:x will be 80u/(x+y) = 80/(1) = 80u.
Therefore, the correct answer is C. 80
Molar ratio of methane to ethene = x:y
Average molecular mass = 20u
Calculation:
Let the molar mass of methane be 'a' and the molar mass of ethene be 'b'.
According to the given data:
(a*x + b*y)/(x+y) = 20
When the molar ratio is reversed (y:x), the new average molar mass will be:
(b*x + a*y)/(x+y)
Substitute the values:
From the given data, we know that:
a = 16u (molar mass of methane)
b = 28u (molar mass of ethene)
Substitute the values into the equation:
(28*x + 16*y)/(x+y)
Simplify the equation:
(28x + 16y)/(x+y) = (4(7x) + 4(4y))/(x+y) = 4(7x + 4y)/(x+y) = 4(20)/(x+y) = 80/(x+y)
Therefore, the mean molar mass when the molar ratio is y:x will be 80u/(x+y).
Final Answer:
The mean molar mass, when they are mixed in molar ratio of y:x will be 80u/(x+y) = 80/(1) = 80u.
Therefore, the correct answer is C. 80
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A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c?
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A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c?.
A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of methane and ethene in molar ratio of x:y has an average molecular mass of 20u.The mean molar mass,when they are mixed in molar ratio of y:x will be ?? A.20 B.25 C.24 D.15 Answer c?.
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