A compound was found to contain 5.37% of nitrogen. What is the minimum...
Explanation:
To find the minimum molecular weight of the compound, we need to assume that all the nitrogen in the compound is present in the form of ammonia (NH3), which has the minimum possible molecular weight among all nitrogen-containing compounds.
Calculations:
Let the molecular weight of the compound be x.
Given, the compound contains 5.37% nitrogen.
Therefore, the mass of nitrogen in the compound = 5.37% of x.
Since all the nitrogen is assumed to be present in the form of ammonia, the mass of ammonia in the compound = mass of nitrogen in the compound / (mass of nitrogen in 1 mole of ammonia)
= (5.37/100)x / (14/3)
= 0.114x
The molecular weight of ammonia (NH3) = 17 g/mol
Therefore, the number of moles of ammonia in the compound = mass of ammonia in the compound / molecular weight of ammonia
= 0.114x / 17
= 0.0067x
Since the compound contains only one molecule of ammonia, the number of moles of the compound = 0.0067x
Therefore, the molecular weight of the compound = mass of the compound / number of moles of the compound
= x / 0.0067x
= 149.25 g/mol
Conclusion:
The minimum molecular weight of the compound is 149.25 g/mol, which is closest to option (D) none.
A compound was found to contain 5.37% of nitrogen. What is the minimum...
Molecular mass of N=14... This qus can be solve by unitary method... If 5.37% weighs 14gm then 100% will have a mass of 100×14/5.37=260.7gm...Hence minimum Molecular weight will be 260.7(C)
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