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How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and
0.90 moles C according to the following reaction ?
0.90 moles C according to the following reaction ?
Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 CO
- a)0.060
- b)0.030
- c)0.045
- d)0.075
Correct answer is option 'A'. Can you explain this answer?
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How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO...
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How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO...
To determine the number of moles of P4 that can be produced, we need to find the limiting reactant in the reaction.
The stoichiometric ratio of the reaction is:
1 mole Ca5(PO4)3F : 18 moles SiO2 : 30 moles C : x moles P4
First, let's find the number of moles of P4 that can be produced from each reactant:
From Ca5(PO4)3F:
1 mole Ca5(PO4)3F : x moles P4
From the stoichiometric ratio, we can see that there is no direct relationship between Ca5(PO4)3F and P4. Therefore, we cannot determine the number of moles of P4 that can be produced from Ca5(PO4)3F.
From SiO2:
18 moles SiO2 : x moles P4
Again, there is no direct relationship between SiO2 and P4, so we cannot determine the number of moles of P4 that can be produced from SiO2.
From C:
30 moles C : x moles P4
Here, we can see that the ratio is 30:1, meaning that for every 30 moles of C, 1 mole of P4 is produced.
Since we have 0.90 moles of C, we can calculate the number of moles of P4 that can be produced by multiplying the number of moles of C by the stoichiometric ratio:
0.90 moles C * (1 mole P4 / 30 moles C) = 0.03 moles P4
Therefore, the number of moles of P4 that can be produced is 0.03 moles.
The stoichiometric ratio of the reaction is:
1 mole Ca5(PO4)3F : 18 moles SiO2 : 30 moles C : x moles P4
First, let's find the number of moles of P4 that can be produced from each reactant:
From Ca5(PO4)3F:
1 mole Ca5(PO4)3F : x moles P4
From the stoichiometric ratio, we can see that there is no direct relationship between Ca5(PO4)3F and P4. Therefore, we cannot determine the number of moles of P4 that can be produced from Ca5(PO4)3F.
From SiO2:
18 moles SiO2 : x moles P4
Again, there is no direct relationship between SiO2 and P4, so we cannot determine the number of moles of P4 that can be produced from SiO2.
From C:
30 moles C : x moles P4
Here, we can see that the ratio is 30:1, meaning that for every 30 moles of C, 1 mole of P4 is produced.
Since we have 0.90 moles of C, we can calculate the number of moles of P4 that can be produced by multiplying the number of moles of C by the stoichiometric ratio:
0.90 moles C * (1 mole P4 / 30 moles C) = 0.03 moles P4
Therefore, the number of moles of P4 that can be produced is 0.03 moles.
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How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and0.90 moles C according to the following reaction ?Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 COa)0.060b)0.030c)0.045d)0.075Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and0.90 moles C according to the following reaction ?Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 COa)0.060b)0.030c)0.045d)0.075Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and0.90 moles C according to the following reaction ?Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 COa)0.060b)0.030c)0.045d)0.075Correct answer is option 'A'. Can you explain this answer?.
How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and0.90 moles C according to the following reaction ?Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 COa)0.060b)0.030c)0.045d)0.075Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and0.90 moles C according to the following reaction ?Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 COa)0.060b)0.030c)0.045d)0.075Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3F, 0.36 moles SiO2 and0.90 moles C according to the following reaction ?Ca5 (PO4)3F + 18 SiO2 + 30 C → 3P4+ 2CaF2 + 18CaSiO3 + 30 COa)0.060b)0.030c)0.045d)0.075Correct answer is option 'A'. Can you explain this answer?.
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