Explanation:

To find the value of (P Q), we need to determine the bond angles of the anionic parts of N2O5 and XeO3F2.

Bond Angle of Anionic Part of N2O5:
N2O5 consists of two nitrogen atoms (N) and five oxygen atoms (O). The anionic part of N2O5 is formed by removing one oxygen atom and leaving behind the negative charge. This anionic part can be represented as [NO3]-.

The structure of [NO3]- is trigonal planar, with the nitrogen atom at the center and three oxygen atoms surrounding it. In a trigonal planar molecule, the bond angle between the central atom and the surrounding atoms is 120°.

Therefore, the bond angle of the anionic part of N2O5 (P) is 120°.

Bond Angle of Anionic Part of XeO3F2:
XeO3F2 consists of one xenon atom (Xe), three oxygen atoms (O), and two fluorine atoms (F). The anionic part of XeO3F2 is formed by removing one fluorine atom and leaving behind the negative charge. This anionic part can be represented as [XeO3F]-.

The structure of [XeO3F]- is tetrahedral, with the xenon atom at the center and three oxygen atoms and one fluorine atom surrounding it. In a tetrahedral molecule, the bond angle between the central atom and the surrounding atoms is 109.5°.

Therefore, the maximum bond angle of the anionic part of XeO3F2 (Q) is 109.5°.

Value of (P Q):
Substituting the values we found earlier, we have:
(P Q) = (120° 109.5°)
= 10.5°

Therefore, the value of (P Q) is 10.5°.