CA Foundation Exam > CA Foundation Questions > No. of radio- active atoms decaying in a give...
Start Learning for Free
No. of radio- active atoms decaying in a given interval of time is an example of
- a)Binomial distribution
- b)Normal distribution
- c)Poisson distribution
- d)None
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
No. of radio- active atoms decaying in a given interval of time is an ...
Poisson distribution is a statistical concept that describes the probability of a given number of events occurring in a fixed interval of time or space. It is used to model the number of times that an event occurs in a given time frame, such as the number of defects in a product or the number of customers who arrive at a store.
Explanation:
In this given problem, we are interested in the number of radioactive atoms that decay in a given interval of time. The decay of radioactive atoms is a random process, and the rate of decay is proportional to the number of atoms present. Therefore, the number of decays that occur in a fixed interval of time follows a Poisson distribution.
The Poisson distribution has the following properties:
- It is a discrete probability distribution that ranges from 0 to infinity.
- The mean and variance of the distribution are equal and are denoted by λ.
- The probability of observing k events in a fixed interval of time is given by the formula:
P(k) = (e^(-λ) * λ^k) / k!
where e is the mathematical constant approximately equal to 2.71828.
In the given problem, the number of decays that occur in a fixed interval of time can be modeled by a Poisson distribution with a mean of λ. The probability of observing k decays in the interval is given by the Poisson distribution formula.
Therefore, the correct answer is option C, Poisson distribution.
Explanation:
In this given problem, we are interested in the number of radioactive atoms that decay in a given interval of time. The decay of radioactive atoms is a random process, and the rate of decay is proportional to the number of atoms present. Therefore, the number of decays that occur in a fixed interval of time follows a Poisson distribution.
The Poisson distribution has the following properties:
- It is a discrete probability distribution that ranges from 0 to infinity.
- The mean and variance of the distribution are equal and are denoted by λ.
- The probability of observing k events in a fixed interval of time is given by the formula:
P(k) = (e^(-λ) * λ^k) / k!
where e is the mathematical constant approximately equal to 2.71828.
In the given problem, the number of decays that occur in a fixed interval of time can be modeled by a Poisson distribution with a mean of λ. The probability of observing k decays in the interval is given by the Poisson distribution formula.
Therefore, the correct answer is option C, Poisson distribution.
Free Test
FREE
| Start Free Test |
Community Answer
No. of radio- active atoms decaying in a given interval of time is an ...
Poisson distribution.....
Attention CA Foundation Students!
To make sure you are not studying endlessly, EduRev has designed CA Foundation study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CA Foundation.
|
Explore Courses for CA Foundation exam
|
|
Similar CA Foundation Doubts
Top Courses for CA FoundationView all
No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer?
Question Description
No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer?.
No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer?.
Solutions for No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for CA Foundation.
Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free.
Here you can find the meaning of No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice No. of radio- active atoms decaying in a given interval of time is an example ofa)Binomial distributionb)Normal distributionc)Poisson distributiond)NoneCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice CA Foundation tests.
|
|
Explore Courses for CA Foundation exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup