JEE Exam > JEE Questions > A heater A gives out 300 W of heat when conne...
Start Learning for Free
A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -
- a)100 W
- b)450 W
- c)300 W
- d)200 W
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A heater A gives out 300 W of heat when connected to a 200 V d.c. supp...
Heat when both resistors are connected in series
Most Upvoted Answer
A heater A gives out 300 W of heat when connected to a 200 V d.c. supp...
Explanation:
1. Heater A and Heater B:
- Heater A gives out 300 W of heat when connected to a 200 V d.c. supply.
- Heater B gives out 600 W when connected to a 200 V d.c. supply.
2. Combined Heat Output:
- When connected in series, the voltage across both heaters will be the same (200 V).
- The total heat output in a series circuit is the sum of the individual heat outputs.
- Therefore, the total heat output when Heater A and Heater B are connected in series is 300 W + 600 W = 900 W.
3. Power in a Series Circuit:
- In a series circuit, the total power is the sum of the powers of the individual components.
- Since the total heat output is 900 W and the total voltage is 200 V, the total power can be calculated using the formula: Power = Voltage x Current.
- Therefore, the total power in the series circuit is 900 W = 200 V x Current. Solving for Current gives Current = 900 W / 200 V = 4.5 A.
4. Heat Output with Series Combination:
- Since the total power in the series circuit is 900 W and the total voltage is 200 V, the total heat output can be calculated using the formula: Power = Voltage x Current.
- Therefore, the total heat output in the series circuit is 200 V x 4.5 A = 900 W.
5. Conclusion:
- The heat output when Heater A and Heater B are connected in series to a 200 V d.c. supply is 900 W, not 200 W as suggested in the options.
- Therefore, the correct answer is option 'D' - 900 W.
1. Heater A and Heater B:
- Heater A gives out 300 W of heat when connected to a 200 V d.c. supply.
- Heater B gives out 600 W when connected to a 200 V d.c. supply.
2. Combined Heat Output:
- When connected in series, the voltage across both heaters will be the same (200 V).
- The total heat output in a series circuit is the sum of the individual heat outputs.
- Therefore, the total heat output when Heater A and Heater B are connected in series is 300 W + 600 W = 900 W.
3. Power in a Series Circuit:
- In a series circuit, the total power is the sum of the powers of the individual components.
- Since the total heat output is 900 W and the total voltage is 200 V, the total power can be calculated using the formula: Power = Voltage x Current.
- Therefore, the total power in the series circuit is 900 W = 200 V x Current. Solving for Current gives Current = 900 W / 200 V = 4.5 A.
4. Heat Output with Series Combination:
- Since the total power in the series circuit is 900 W and the total voltage is 200 V, the total heat output can be calculated using the formula: Power = Voltage x Current.
- Therefore, the total heat output in the series circuit is 200 V x 4.5 A = 900 W.
5. Conclusion:
- The heat output when Heater A and Heater B are connected in series to a 200 V d.c. supply is 900 W, not 200 W as suggested in the options.
- Therefore, the correct answer is option 'D' - 900 W.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer?
Question Description
A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer?.
A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer?.
Solutions for A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A heater A gives out 300 W of heat when connected to a 200 V d.c. supply. A second heater B gives out 600 W when connected to a 200 V d.c. supply. If a series combination of the two heaters is connected to a 200 V d.c. supply the heat output will be -a)100 Wb)450 Wc)300 Wd)200 WCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup