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If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is
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If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: ...
Explanation:
The given sub duplicate ratio is p:q, which means p is the square root of (2q).
Let the original ratio be (p-x^2) : (q-x^2).
Using the formula for sub-duplicate ratio, we can say that (p-x^2) is the square root of (2(q-x^2)).
Squaring both sides, we get:
(p-x^2)^2 = 2(q-x^2)
Expanding the left side, we get:
p^2 - 2px^2 + x^4 = 2q - 2x^2
Rearranging, we get:
p^2 - 2q = 2px^2 - x^4 + 2x^2
Simplifying, we get:
(p^2 - 2q) = 2x^2(p - x^2)
Dividing both sides by (p - x^2), we get:
(p^2 - 2q)/(p - x^2) = 2x^2
Therefore, x^2 is given by:
x^2 = (p^2 - 2q)/(2(p - x^2))
Conclusion:
In conclusion, we have derived the expression for x^2 in terms of the given sub-duplicate ratio.
The given sub duplicate ratio is p:q, which means p is the square root of (2q).
Let the original ratio be (p-x^2) : (q-x^2).
Using the formula for sub-duplicate ratio, we can say that (p-x^2) is the square root of (2(q-x^2)).
Squaring both sides, we get:
(p-x^2)^2 = 2(q-x^2)
Expanding the left side, we get:
p^2 - 2px^2 + x^4 = 2q - 2x^2
Rearranging, we get:
p^2 - 2q = 2px^2 - x^4 + 2x^2
Simplifying, we get:
(p^2 - 2q) = 2x^2(p - x^2)
Dividing both sides by (p - x^2), we get:
(p^2 - 2q)/(p - x^2) = 2x^2
Therefore, x^2 is given by:
x^2 = (p^2 - 2q)/(2(p - x^2))
Conclusion:
In conclusion, we have derived the expression for x^2 in terms of the given sub-duplicate ratio.
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If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)?
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If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)?.
If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If p:q is the sub dublicate ratio of p-x^2:q-x^2 the x^2 is Related: Ratio and Proportion, Indices, Logarithms (Part - 1)?.
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