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A particle of mass m is projected with velocity υ making an angle of 45° with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)a)Zerob)mυ3/(4√2g)c)mυ3/(√2g)d)mυ2/2gCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle of mass m is projected with velocity υ making an angle of 45° with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)a)Zerob)mυ3/(4√2g)c)mυ3/(√2g)d)mυ2/2gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass m is projected with velocity υ making an angle of 45° with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)a)Zerob)mυ3/(4√2g)c)mυ3/(√2g)d)mυ2/2gCorrect answer is option 'B'. Can you explain this answer?.

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