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A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10−2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.
  • a)
    1.1 cm
  • b)
    1.0 cm
  • c)
    0.9 cm
  • d)
    1.2 cm 
Correct answer is option 'A'. Can you explain this answer?
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A mild steel wire of length 1.0 m and cross-sectional area 0.50 ×...


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A mild steel wire of length 1.0 m and cross-sectional area 0.50 ×...
To find the resistance of the wire, we can use the formula:

R = ρ * (L/A)

Where:
R = Resistance
ρ = Resistivity of the material (for mild steel, ρ = 1.59 x 10^-8 Ωm)
L = Length of the wire (L = 1.0 m)
A = Cross-sectional area of the wire (A = 0.50 mm² = 0.50 x 10^-6 m²)

Plugging in the values, we get:

R = (1.59 x 10^-8 Ωm) * (1.0 m / 0.50 x 10^-6 m²)
R = 31.8 Ω

Therefore, the resistance of the mild steel wire is 31.8 Ω.
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A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10−2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.a)1.1 cmb)1.0 cmc)0.9 cmd)1.2 cmCorrect answer is option 'A'. Can you explain this answer?
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A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10−2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.a)1.1 cmb)1.0 cmc)0.9 cmd)1.2 cmCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10−2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.a)1.1 cmb)1.0 cmc)0.9 cmd)1.2 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10−2 cm2 is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.a)1.1 cmb)1.0 cmc)0.9 cmd)1.2 cmCorrect answer is option 'A'. Can you explain this answer?.
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