Determine the least number which when divided by 3 , 4 and 5 leaves re...
Problem: Determine the least number which when divided by 3, 4, and 5 leaves a remainder of 2 in each case.
Solution:
To solve this problem, we need to find the least common multiple (LCM) of 3, 4, and 5 and then add 2 to it.
Finding LCM:
We can find the LCM of 3, 4, and 5 by prime factorizing each number and then taking the highest power of each prime factor.
Prime factorization of 3: 3
Prime factorization of 4: 2 x 2
Prime factorization of 5: 5
So, the LCM of 3, 4, and 5 would be 2 x 2 x 3 x 5 = 60.
Adding Remainder:
Now, we add 2 to the LCM to get the required number.
60 + 2 = 62
Therefore, the least number which when divided by 3, 4, and 5 leaves a remainder of 2 in each case is 62.
Explanation:
When we divide 62 by 3, we get a remainder of 2. Similarly, when we divide 62 by 4 and 5, we also get a remainder of 2. This is because 62 is 2 more than the LCM of 3, 4, and 5, which means that it leaves a remainder of 2 when divided by each of these numbers.
Conclusion:
The required number is 62.
Determine the least number which when divided by 3 , 4 and 5 leaves re...
You have to take firstly lcm of the given numbers means 3,4 and 5
so the lcm comes 60.
Now we have to add given remainder (2) = 62
So, the number comes 62.
PROOF-..
if we divide :- 62 by 3 remainder comes 2.
if we divide 62 by 4 remainder comes 2.
if we divide 62 by 5 remainder comes 2.
To make sure you are not studying endlessly, EduRev has designed Class 6 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 6.