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By X-ray studies, the packing of atoms in a crystal of gold is found to be in layers such that starting from any layer, every fourth layer is found to be exactly identical. The density of gold is found to be 19.4 g/cm3 and its atomic mass is 197 amu.The length of the edge of the unit cell will be:a)407b)606c)132d)260Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about By X-ray studies, the packing of atoms in a crystal of gold is found to be in layers such that starting from any layer, every fourth layer is found to be exactly identical. The density of gold is found to be 19.4 g/cm3 and its atomic mass is 197 amu.The length of the edge of the unit cell will be:a)407b)606c)132d)260Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for By X-ray studies, the packing of atoms in a crystal of gold is found to be in layers such that starting from any layer, every fourth layer is found to be exactly identical. The density of gold is found to be 19.4 g/cm3 and its atomic mass is 197 amu.The length of the edge of the unit cell will be:a)407b)606c)132d)260Correct answer is option 'A'. Can you explain this answer?.

Solutions for By X-ray studies, the packing of atoms in a crystal of gold is found to be in layers such that starting from any layer, every fourth layer is found to be exactly identical. The density of gold is found to be 19.4 g/cm3 and its atomic mass is 197 amu.The length of the edge of the unit cell will be:a)407b)606c)132d)260Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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