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Which of the following series is divergent?
  • a)
  • b)
  • c)
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
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Which of the following series is divergent?a)b)c)d)None of theseCorrec...
The series Sigma [sin(1/n)] is a divergent series, because
lim(n-->inf.)[sin(1/n)]/(1/n) = 1, which is nonzero, which in turn is a consequence of lim(x-->0)[sin(x)]/x = 1. Hence the two series Sigma [sin(1/n)] and Sigma(1/n) have the same convergence behaviour by limit comparison test, for series of positive terms But we know that the harmonic series Sigma(1/n) diverges. Hence the given series Sigma[sin(1/n) also diverges.
Note that for all 1 </= n, 0 < (1/n) </= 1 < π, and so sin(1/n) is positive i.e. the given series is of positive terms.
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Which of the following series is divergent?a)b)c)d)None of theseCorrec...
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Which of the following series is divergent?a)b)c)d)None of theseCorrec...
B option sin1/n^2 is absolutely convergent, it is not divergent,..by comparison test.....
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