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The weight of an object at the centre of the earth of radius R is
- a)zero
- b)infinite
- c)R times the weight at the surface of the earth
- d)1/R2 times the weight at the surface of the earth
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The weight of an object at the centre of the earth of radius R isa)zer...
At the center of the earth , it's radius will be zero .
so weight of an object will be also 0.
so weight of an object will be also 0.
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The weight of an object at the centre of the earth of radius R isa)zer...
Weight at the Centre of the Earth
Weight is the force with which an object is pulled towards the center of the Earth due to the gravitational attraction. The weight of an object depends on its mass and the gravitational force acting on it.
Gravitational Force
The gravitational force acting on an object is directly proportional to its mass and inversely proportional to the square of the distance between the object and the center of the Earth. This relationship is described by the equation:
F = G * (M * m) / r^2
Where F is the gravitational force, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object, and r is the distance between the object and the center of the Earth.
Weight at the Surface of the Earth
At the surface of the Earth, the weight of an object is equal to the gravitational force acting on it. This can be calculated using the equation:
Weight = m * g
Where m is the mass of the object and g is the acceleration due to gravity, approximately equal to 9.8 m/s^2.
Weight at the Centre of the Earth
At the centre of the Earth, the distance between the object and the center of the Earth is zero (r = 0). Plugging this value into the equation for gravitational force, we get:
F = G * (M * m) / 0^2
Since any number divided by zero is undefined, the gravitational force at the centre of the Earth is undefined. Therefore, the weight of an object at the centre of the Earth is zero.
Conclusion
The weight of an object at the centre of the Earth is zero because the distance between the object and the center of the Earth is zero. This means that the gravitational force acting on the object is undefined.
Weight is the force with which an object is pulled towards the center of the Earth due to the gravitational attraction. The weight of an object depends on its mass and the gravitational force acting on it.
Gravitational Force
The gravitational force acting on an object is directly proportional to its mass and inversely proportional to the square of the distance between the object and the center of the Earth. This relationship is described by the equation:
F = G * (M * m) / r^2
Where F is the gravitational force, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object, and r is the distance between the object and the center of the Earth.
Weight at the Surface of the Earth
At the surface of the Earth, the weight of an object is equal to the gravitational force acting on it. This can be calculated using the equation:
Weight = m * g
Where m is the mass of the object and g is the acceleration due to gravity, approximately equal to 9.8 m/s^2.
Weight at the Centre of the Earth
At the centre of the Earth, the distance between the object and the center of the Earth is zero (r = 0). Plugging this value into the equation for gravitational force, we get:
F = G * (M * m) / 0^2
Since any number divided by zero is undefined, the gravitational force at the centre of the Earth is undefined. Therefore, the weight of an object at the centre of the Earth is zero.
Conclusion
The weight of an object at the centre of the Earth is zero because the distance between the object and the center of the Earth is zero. This means that the gravitational force acting on the object is undefined.
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The weight of an object at the centre of the earth of radius R isa)zerob)infinitec)R times the weight at the surface of the earthd)1/R2times the weight at the surface of the earthCorrect answer is option 'A'. Can you explain this answer?
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