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5,000 students were appeared in an examination. The mean of marks was 39.5 with a Standard Deviation 12.5 marks. Assuming the distribution to be normal, find the number of students recorded more than 60% marks.Given: When Z = 1.64, aREA OF NORMAL CURVE = 0.4495a)1,000b)505c)252d)2,227Correct answer is option 'C'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about 5,000 students were appeared in an examination. The mean of marks was 39.5 with a Standard Deviation 12.5 marks. Assuming the distribution to be normal, find the number of students recorded more than 60% marks.Given: When Z = 1.64, aREA OF NORMAL CURVE = 0.4495a)1,000b)505c)252d)2,227Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5,000 students were appeared in an examination. The mean of marks was 39.5 with a Standard Deviation 12.5 marks. Assuming the distribution to be normal, find the number of students recorded more than 60% marks.Given: When Z = 1.64, aREA OF NORMAL CURVE = 0.4495a)1,000b)505c)252d)2,227Correct answer is option 'C'. Can you explain this answer?.

Solutions for 5,000 students were appeared in an examination. The mean of marks was 39.5 with a Standard Deviation 12.5 marks. Assuming the distribution to be normal, find the number of students recorded more than 60% marks.Given: When Z = 1.64, aREA OF NORMAL CURVE = 0.4495a)1,000b)505c)252d)2,227Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for CA Foundation. Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free.

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