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Two masses m and 2m are dropped from certain height ‘h’. Then on reaching the ground,
- a)K.E. of them will be equal
- b)K.E. of the heavier is 4 times the K.E. of the lighter
- c)K.E. of the lighter is 4 times the K.E. of the heavier
- d)K.E. of the heavier is more than that of the lighter.
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Two masses m and 2m are dropped from certain height ‘h’. T...
- Since the free-falling acceleration is not dependent on mass, the final velocities of both masses are the same.
The kinetic energy = KE = mv2/2 - Hence, the kinetic energy of the heavier mass will be more.
Most Upvoted Answer
Two masses m and 2m are dropped from certain height ‘h’. T...
When two objects of different masses are dropped from a certain height, they will fall towards the ground due to the force of gravity. The acceleration due to gravity, denoted as "g," is constant and is approximately 9.8 m/s^2 on Earth.
Since both masses are dropped from the same height, they will experience the same gravitational force. According to Newton's second law of motion, the force acting on an object is equal to the product of its mass and acceleration. Therefore, the force acting on the mass "m" is m * g, and the force acting on the mass "2m" is (2m) * g = 2mg.
As a result, the acceleration experienced by the mass "m" is given by the equation F = m * a, where "F" is the force and "a" is the acceleration. By substituting the force as mg, we get:
mg = m * a
Simplifying the equation, we find:
g = a
This means that both masses will have the same acceleration, regardless of their individual masses.
Therefore, both masses will fall towards the ground with the same acceleration of approximately 9.8 m/s^2. However, the mass "2m" will experience twice the force as the mass "m" due to its greater mass.
Since both masses are dropped from the same height, they will experience the same gravitational force. According to Newton's second law of motion, the force acting on an object is equal to the product of its mass and acceleration. Therefore, the force acting on the mass "m" is m * g, and the force acting on the mass "2m" is (2m) * g = 2mg.
As a result, the acceleration experienced by the mass "m" is given by the equation F = m * a, where "F" is the force and "a" is the acceleration. By substituting the force as mg, we get:
mg = m * a
Simplifying the equation, we find:
g = a
This means that both masses will have the same acceleration, regardless of their individual masses.
Therefore, both masses will fall towards the ground with the same acceleration of approximately 9.8 m/s^2. However, the mass "2m" will experience twice the force as the mass "m" due to its greater mass.
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Community Answer
Two masses m and 2m are dropped from certain height ‘h’. T...
Option c is correct.
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Two masses m and 2m are dropped from certain height ‘h’. Then on reaching the ground,a)K.E. of them will be equalb)K.E. of the heavier is 4 times the K.E. of the lighterc)K.E. of the lighter is 4 times the K.E. of the heavierd)K.E. of the heavier is more than that of the lighter.Correct answer is option 'D'. Can you explain this answer?
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Two masses m and 2m are dropped from certain height ‘h’. Then on reaching the ground,a)K.E. of them will be equalb)K.E. of the heavier is 4 times the K.E. of the lighterc)K.E. of the lighter is 4 times the K.E. of the heavierd)K.E. of the heavier is more than that of the lighter.Correct answer is option 'D'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Two masses m and 2m are dropped from certain height ‘h’. Then on reaching the ground,a)K.E. of them will be equalb)K.E. of the heavier is 4 times the K.E. of the lighterc)K.E. of the lighter is 4 times the K.E. of the heavierd)K.E. of the heavier is more than that of the lighter.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two masses m and 2m are dropped from certain height ‘h’. Then on reaching the ground,a)K.E. of them will be equalb)K.E. of the heavier is 4 times the K.E. of the lighterc)K.E. of the lighter is 4 times the K.E. of the heavierd)K.E. of the heavier is more than that of the lighter.Correct answer is option 'D'. Can you explain this answer?.
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