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5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c?
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Calculation of Osmotic Pressure of 5g/L Polymer Solution
Given:
- Concentration of Polymer Solution (C) = 5 g/L
- Molecular Mass of Polymer (M) = 25 kg
Formula:
- Osmotic Pressure (π) = (C * R * T) / M
where
- R = Gas Constant = 0.08206 L atm K^-1 mol^-1
- T = Temperature = 25 + 273 = 298 K
Calculation:
- Osmotic Pressure (π) = (5 g/L * 0.08206 L atm K^-1 mol^-1 * 298 K) / (25 kg)
- π = 0.0124 atm
Explanation:
- Osmotic Pressure is defined as the pressure required to prevent the movement of solvent molecules across a semipermeable membrane from a region of low solute concentration to a region of high solute concentration.
- In this case, the solute is the polymer and the solvent is the water.
- The formula for calculating osmotic pressure of a solution is given by π = (C * R * T) / M, where C is the concentration of the solution, R is the gas constant, T is the temperature in Kelvin, and M is the molecular mass of the solute.
- Substituting the given values in the formula, we get the osmotic pressure of the 5g/L polymer solution at 25°C.
- The osmotic pressure of the solution is 0.0124 atm.
Given:
- Concentration of Polymer Solution (C) = 5 g/L
- Molecular Mass of Polymer (M) = 25 kg
Formula:
- Osmotic Pressure (π) = (C * R * T) / M
where
- R = Gas Constant = 0.08206 L atm K^-1 mol^-1
- T = Temperature = 25 + 273 = 298 K
Calculation:
- Osmotic Pressure (π) = (5 g/L * 0.08206 L atm K^-1 mol^-1 * 298 K) / (25 kg)
- π = 0.0124 atm
Explanation:
- Osmotic Pressure is defined as the pressure required to prevent the movement of solvent molecules across a semipermeable membrane from a region of low solute concentration to a region of high solute concentration.
- In this case, the solute is the polymer and the solvent is the water.
- The formula for calculating osmotic pressure of a solution is given by π = (C * R * T) / M, where C is the concentration of the solution, R is the gas constant, T is the temperature in Kelvin, and M is the molecular mass of the solute.
- Substituting the given values in the formula, we get the osmotic pressure of the 5g/L polymer solution at 25°C.
- The osmotic pressure of the solution is 0.0124 atm.
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5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c?
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5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about 5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c?.
5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about 5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5g/L polymer solution is prepared with a polymer whose molecular mass is 25kg.the osmotic pressure in atm of the solution at 25c?.
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