Question Description
Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer?.

Solutions for Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mathematics. Download more important topics, notes, lectures and mock test series for Mathematics Exam by signing up for free.

Here you can find the meaning of Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Let < an > and < bn> be two sequences of real numbers such that an = bn - bn + 1for n = 1, 2 , 3 , 4 , . . . if Sbn is convergent, then which is always true?a)San may not be convergentb)San is convergent and San = b1c)San is convergent and San = 0d)San is convergent and San = a1- b1e)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Mathematics tests.