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Assuming that the volume of water does not change on dissolving NaCl, the density of a 0.1 M aqueous solution of NaCl at 25 degree celsius (atomic weight of Na= 23.0 and Cl= 35.5)?

a) 0.93 g/mL
b) 1.00 g/mL
c) 1.01 g/mL
d) 1.10 g/mL?
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Assuming that the volume of water does not change on dissolving NaCl, ...
Solution:

The molar mass of NaCl is 23.0 + 35.5 = 58.5 g/mol.

The concentration of the solution is 0.1 M, which means that for every liter of solution, there are 0.1 moles of NaCl.

The mass of 0.1 moles of NaCl is:

0.1 mol x 58.5 g/mol = 5.85 g

Assuming that the volume of water does not change on dissolving NaCl, the density of the solution can be calculated as:

density = mass/volume

Since the volume of solution is 1 L, the density is:

density = 5.85 g/1 L = 5.85 g/mL

However, this is the density of the solid NaCl. To find the density of the solution, we need to consider the volume of the NaCl and the volume of the water.

The volume of 0.1 moles of NaCl is:

0.1 mol x (1 L/1000 mL) x (1 cm^3/1 mL) = 0.1 cm^3

The volume of 1 L of water is 1000 cm^3.

Therefore, the total volume of the solution is:

0.1 cm^3 + 1000 cm^3 = 1000.1 cm^3

The density of the solution is:

density = mass/volume = 5.85 g/1000.1 cm^3

Using the conversion factor 1 cm^3 = 1 mL, the density can be expressed in g/mL:

density = 5.85 g/1000.1 mL = 0.005849 g/mL

Therefore, the correct answer is:

a) 0.93 g/mL
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Assuming that the volume of water does not change on dissolving NaCl, the density of a 0.1 M aqueous solution of NaCl at 25 degree celsius (atomic weight of Na= 23.0 and Cl= 35.5)?a) 0.93 g/mLb) 1.00 g/mLc) 1.01 g/mLd) 1.10 g/mL?
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Assuming that the volume of water does not change on dissolving NaCl, the density of a 0.1 M aqueous solution of NaCl at 25 degree celsius (atomic weight of Na= 23.0 and Cl= 35.5)?a) 0.93 g/mLb) 1.00 g/mLc) 1.01 g/mLd) 1.10 g/mL? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Assuming that the volume of water does not change on dissolving NaCl, the density of a 0.1 M aqueous solution of NaCl at 25 degree celsius (atomic weight of Na= 23.0 and Cl= 35.5)?a) 0.93 g/mLb) 1.00 g/mLc) 1.01 g/mLd) 1.10 g/mL? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming that the volume of water does not change on dissolving NaCl, the density of a 0.1 M aqueous solution of NaCl at 25 degree celsius (atomic weight of Na= 23.0 and Cl= 35.5)?a) 0.93 g/mLb) 1.00 g/mLc) 1.01 g/mLd) 1.10 g/mL?.
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