The mean for counting numbers through 100 isa)47.5b)51c)50.5d)49.5Corr...
First 100 postive numbers are:
1, 2, 3,4,5, .....100.
These number are in AP.
Sum of AP is given by,
{n * (a + l) /2} [Where a = first term, n = number of terms, l = last term.]
= 100 * (1 +100)/2 = 50 * 101.
Required Average = (50 *101)/100 = 50.5.
Short-Cut:
For an AP series,
Average = (first term + last term) /2
For above given series average,
= ( 1 +100)/2 = 50.5.
The mean for counting numbers through 100 isa)47.5b)51c)50.5d)49.5Corr...
Explanation:
The mean of a set of numbers is the sum of all the numbers in the set divided by the total number of numbers in the set.
In this case, we are looking for the mean of counting numbers through 100, which means we need to find the sum of all the numbers from 1 to 100 and divide that sum by the total number of numbers in the set (which is 100).
Calculating the sum of counting numbers through 100:
We can use the formula for the sum of an arithmetic series to find the sum of counting numbers through 100:
S = (n/2)(a + l)
where S is the sum, n is the number of terms, a is the first term, and l is the last term.
In this case, n = 100, a = 1, and l = 100, so we can plug in these values and simplify:
S = (100/2)(1 + 100)
S = 50(101)
S = 5050
So the sum of counting numbers through 100 is 5050.
Calculating the mean:
Now that we have the sum, we can find the mean:
mean = sum/number of terms
mean = 5050/100
mean = 50.5
Therefore, the mean of counting numbers through 100 is 50.5.