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NH₃ and BF₃ form an adduct readily because they form
  • a)
    A coordinate bond
  • b)
    A hydrogen bond
  • c)
    An ionic bond
  • d)
    A covalent bond
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
NH and BF form an adduct readily because they forma)A coordinate bondb...
Coordinate Bond Formation between NH and BF

- Introduction: The formation of an adduct between NH (ammonia) and BF (boron trifluoride) can be explained by the presence of a coordinate bond between the two compounds.

- Coordinate Bond: A coordinate bond is a type of covalent bond in which both electrons are supplied by one atom. One atom, called the donor, donates a pair of electrons to another atom, called the acceptor. This results in the formation of a coordinate bond.

- Formation of the Adduct: NH acts as a donor atom due to the presence of a lone pair of electrons on the nitrogen atom. BF acts as an acceptor atom due to the presence of an empty orbital on the boron atom.

- Donation of Electron Pair: The lone pair of electrons on the nitrogen atom of NH is donated to the empty orbital on the boron atom of BF. This results in the formation of a coordinate bond between the two compounds.

- Stability of the Adduct: The formation of the coordinate bond between NH and BF enhances the stability of the adduct. This is because the bond formation allows for the complete filling of the empty orbital on the boron atom, satisfying its electronic configuration.

- Polar Nature of the Adduct: The adduct formed between NH and BF is polar in nature. This is due to the difference in electronegativity between nitrogen and boron atoms. Nitrogen is more electronegative than boron, resulting in an uneven distribution of electron density in the adduct.

- Applications: The formation of adducts through coordinate bond formation is a common phenomenon in chemistry. It is widely used in various chemical reactions and processes.

- Conclusion: The adduct formation between NH and BF readily occurs due to the formation of a coordinate bond. This bond allows for the donation of a lone pair of electrons from NH to BF, resulting in enhanced stability and polar nature of the adduct.
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NH and BF form an adduct readily because they forma)A coordinate bondb...
It is a coordinate bond as NH3(Lewis base) donates its lone pair to the vacant orbital of BF3(Lewis acid).
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NH and BF form an adduct readily because they forma)A coordinate bondb)A hydrogen bondc)An ionic bondd)A covalent bondCorrect answer is option 'A'. Can you explain this answer?
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NH and BF form an adduct readily because they forma)A coordinate bondb)A hydrogen bondc)An ionic bondd)A covalent bondCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about NH and BF form an adduct readily because they forma)A coordinate bondb)A hydrogen bondc)An ionic bondd)A covalent bondCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for NH and BF form an adduct readily because they forma)A coordinate bondb)A hydrogen bondc)An ionic bondd)A covalent bondCorrect answer is option 'A'. Can you explain this answer?.
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