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The sound of an aeroplane taking off is about 2.2 times louder than a person shouting. Which is the best estimate of the decibel level of an aeroplane taking off if the decibel level of a person shouting is 65.4?
- a)340
- b)140
- c)200
- d)100
Correct answer is option 'B'. Can you explain this answer?
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The sound of an aeroplane taking off is about 2.2 times louder than a ...
The decibel level of an aeroplane taking off can be estimated by considering the ratio between the sound levels of a person shouting and an aeroplane taking off.
Given:
The decibel level of a person shouting = 65.4
The sound of an aeroplane taking off is about 2.2 times louder than a person shouting.
To estimate the decibel level of an aeroplane taking off, we can use the following formula:
Decibel level of aeroplane taking off = Decibel level of person shouting + 10 * log10(Ratio)
Where:
Decibel level of person shouting = 65.4 (given)
Ratio = 2.2 (given)
Substituting the given values into the formula:
Decibel level of aeroplane taking off = 65.4 + 10 * log10(2.2)
Solving the equation:
Decibel level of aeroplane taking off = 65.4 + 10 * 0.3424
Decibel level of aeroplane taking off = 65.4 + 3.424
Decibel level of aeroplane taking off ≈ 68.824
Therefore, the best estimate of the decibel level of an aeroplane taking off is approximately 68.824.
Explanation:
The decibel scale is logarithmic, which means that a small change in the decibel level represents a large change in the sound intensity. In this case, the aeroplane taking off is approximately 2.2 times louder than a person shouting. By using the logarithmic formula, we can estimate the decibel level of the aeroplane taking off.
The formula takes the decibel level of the person shouting and adds 10 times the logarithm (base 10) of the ratio between the sound levels. In this case, the ratio is 2.2.
By substituting the given values into the formula and solving the equation, we find that the estimated decibel level of the aeroplane taking off is approximately 68.824.
This means that the sound of an aeroplane taking off is significantly louder than a person shouting, with a difference of approximately 3.424 decibels.
Given:
The decibel level of a person shouting = 65.4
The sound of an aeroplane taking off is about 2.2 times louder than a person shouting.
To estimate the decibel level of an aeroplane taking off, we can use the following formula:
Decibel level of aeroplane taking off = Decibel level of person shouting + 10 * log10(Ratio)
Where:
Decibel level of person shouting = 65.4 (given)
Ratio = 2.2 (given)
Substituting the given values into the formula:
Decibel level of aeroplane taking off = 65.4 + 10 * log10(2.2)
Solving the equation:
Decibel level of aeroplane taking off = 65.4 + 10 * 0.3424
Decibel level of aeroplane taking off = 65.4 + 3.424
Decibel level of aeroplane taking off ≈ 68.824
Therefore, the best estimate of the decibel level of an aeroplane taking off is approximately 68.824.
Explanation:
The decibel scale is logarithmic, which means that a small change in the decibel level represents a large change in the sound intensity. In this case, the aeroplane taking off is approximately 2.2 times louder than a person shouting. By using the logarithmic formula, we can estimate the decibel level of the aeroplane taking off.
The formula takes the decibel level of the person shouting and adds 10 times the logarithm (base 10) of the ratio between the sound levels. In this case, the ratio is 2.2.
By substituting the given values into the formula and solving the equation, we find that the estimated decibel level of the aeroplane taking off is approximately 68.824.
This means that the sound of an aeroplane taking off is significantly louder than a person shouting, with a difference of approximately 3.424 decibels.
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The sound of an aeroplane taking off is about 2.2 times louder than a person shouting. Which is the best estimate of the decibel level of an aeroplane taking off if the decibel level of a person shouting is 65.4?a)340b)140c)200d)100Correct answer is option 'B'. Can you explain this answer?
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