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A force acting on a mass 0.5kg displaces it to 10m in the first second by how much will it displaces the mass in next second.?
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A force acting on a mass 0.5kg displaces it to 10m in the first second...
Calculation of Displacement in the Next Second:

Given:
- Mass (m) = 0.5 kg
- Displacement in the first second (s1) = 10 m

Step 1: Calculate the acceleration using Newton's second law:
- Force (F) = mass (m) x acceleration (a)
- Using F = ma, we get:
- a = F/m

Step 2: Calculate the acceleration:
- Given force acting on the mass = F
- Let's assume the force acting on the mass is 10 N (for example)
- Therefore, acceleration (a) = 10 N / 0.5 kg = 20 m/s^2

Step 3: Calculate the displacement in the next second:
- Using the equation of motion: s = ut + (1/2)at^2
- Initial velocity (u) is 0 m/s (as the mass starts from rest)
- Time (t) is 1 second
- Substituting the values, we get:
- s = 0 + (1/2) x 20 x (1)^2
- s = 10 m

Conclusion:
- The mass will be displaced by 10 meters in the next second if a constant force of 10 N is applied to it.
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A force acting on a mass 0.5kg displaces it to 10m in the first second by how much will it displaces the mass in next second.?
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