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If the sum of northings of a traverse exceeds the sum of southings by 1 m and sum of eastings exceeds the sum of westirigs by 1 m, the resultant closing error and its true bearing respectively are
  • a)
    1 m, N45°E
  • b)
    2m,N45°W
  • c)
  • d)
    0, N45°E
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If the sum of northings of a traverse exceeds the sum of southings by ...
B)1 m, S45
c)2 m, N45
d)2 m, S45

Answer: a) 1 m, N45

Explanation:

In a traverse, the closing error is the difference between the sum of the eastings and the sum of the westings, and the difference between the sum of the northings and the sum of the southings.

Given,

Sum of northings > Sum of southings by 1 m

Sum of eastings > Sum of westings by 1 m

So, the closing error would be the difference between these two:

Closing error = (Sum of eastings - Sum of westings) + (Sum of northings - Sum of southings)

= 1 + 1

= 2 m

The true bearing of the closing error can be found using the formula:

tan θ = (Sum of eastings - Sum of westings) / (Sum of northings - Sum of southings)

tan θ = 1/1

θ = tan-1(1)

θ = 45°

Since the sum of eastings is greater than the sum of westings, the closing error is to the north of the starting point. Therefore, the true bearing of the closing error is N45.
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Community Answer
If the sum of northings of a traverse exceeds the sum of southings by ...
Closing error is equal to e = √ total error in L² + total error in D²
= √1²+1²=√2
direction of error will be
tan thita =eD/eL
tan thita =1/1 =1
thita =45
at N45E because error will be there when we plot on graph in coordination system
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If the sum of northings of a traverse exceeds the sum of southings by 1 m and sum of eastings exceeds the sum of westirigsby 1 m, the resultant closing error and its true bearing respectively area)1 m, N45°Eb)2m,N45°Wc)d)0, N45°ECorrect answer is option 'C'. Can you explain this answer?
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