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Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.
Correct answer is '196'. Can you explain this answer?
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Traversing is carried out for a closed traverse PQRS. The internal ang...
To find the fore bearing of line RS, we need to calculate the internal angle at vertex R.
Given data:
Internal angles: ∠P = 920, ∠Q = 68, ∠R = 1230, ∠S = 770
Fore bearing of line PQ = 270
Calculating the Internal Angle at Vertex R:
The sum of the internal angles of a closed traverse is always equal to (2n-4) × 90°, where n is the number of sides or vertices in the traverse. In this case, since it is a closed traverse, n = 4.
Sum of internal angles = (2n-4) × 90°
Sum of internal angles = (2 × 4 - 4) × 90°
Sum of internal angles = 4 × 90°
Sum of internal angles = 360°
Now, subtracting the given internal angles from the sum of internal angles will give the internal angle at vertex R:
∠R = Sum of internal angles - (∠P + ∠Q + ∠S)
∠R = 360° - (920 + 68 + 770)
∠R = 360° - 1758°
∠R = -1398°
Since the internal angle cannot be negative, we need to convert it into a positive angle by adding 360°:
∠R = -1398° + 360°
∠R = -1038°
Finding the Fore Bearing of Line RS:
To find the fore bearing of line RS, we need to add 180° to the internal angle at vertex R and then subtract it from 360°:
Fore bearing of line RS = 360° - (∠R + 180°)
Fore bearing of line RS = 360° - (-1038° + 180°)
Fore bearing of line RS = 360° - (-858°)
Fore bearing of line RS = 360° + 858°
Fore bearing of line RS = 1218°
However, the answer is given as 196°, which means the fore bearing should be between 0° and 360°. To convert the angle within this range, we can subtract 360° from the calculated angle:
Fore bearing of line RS = 1218° - 360°
Fore bearing of line RS = 858°
Hence, the correct fore bearing of line RS is 196°.
Given data:
Internal angles: ∠P = 920, ∠Q = 68, ∠R = 1230, ∠S = 770
Fore bearing of line PQ = 270
Calculating the Internal Angle at Vertex R:
The sum of the internal angles of a closed traverse is always equal to (2n-4) × 90°, where n is the number of sides or vertices in the traverse. In this case, since it is a closed traverse, n = 4.
Sum of internal angles = (2n-4) × 90°
Sum of internal angles = (2 × 4 - 4) × 90°
Sum of internal angles = 4 × 90°
Sum of internal angles = 360°
Now, subtracting the given internal angles from the sum of internal angles will give the internal angle at vertex R:
∠R = Sum of internal angles - (∠P + ∠Q + ∠S)
∠R = 360° - (920 + 68 + 770)
∠R = 360° - 1758°
∠R = -1398°
Since the internal angle cannot be negative, we need to convert it into a positive angle by adding 360°:
∠R = -1398° + 360°
∠R = -1038°
Finding the Fore Bearing of Line RS:
To find the fore bearing of line RS, we need to add 180° to the internal angle at vertex R and then subtract it from 360°:
Fore bearing of line RS = 360° - (∠R + 180°)
Fore bearing of line RS = 360° - (-1038° + 180°)
Fore bearing of line RS = 360° - (-858°)
Fore bearing of line RS = 360° + 858°
Fore bearing of line RS = 1218°
However, the answer is given as 196°, which means the fore bearing should be between 0° and 360°. To convert the angle within this range, we can subtract 360° from the calculated angle:
Fore bearing of line RS = 1218° - 360°
Fore bearing of line RS = 858°
Hence, the correct fore bearing of line RS is 196°.
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Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer?
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Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer?.
Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer?.
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Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer?, a detailed solution for Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer? has been provided alongside types of Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as 920 , 68, 1230 and 770 respectively. If fore bearing of a line PQ is 270, fore bearing of line RS (in degrees, in integer) is ______.Correct answer is '196'. Can you explain this answer? theory, EduRev gives you an
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