A parcel lorry came into city with the average speed of 90km/hr. On th...
As we know, Speed = Distance / Time, Therefore Average Speed = Total Distance / Total Time.
Let us assume, Time taken to come to the city = T1
Time taken to go back = T2
Speed while coming to city = V1
Speed while going back = V2
Therefore, T1 = D / V1
and T2 = D / V2
Formulae for Average Speed =>> Average Speed = Distance (coming to city) + Distance (going back)
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T1 + T2
Let us now substitute the formula of T1 and T2, respectively:-
Average Speed = D + D
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D/V1 + D/V2
Average Speed = 2D
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D (1/V1 + 1/V2)
We can now cancel 2D by the denominator D,
Average Speed = 2
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1/V1 + 1/V2
Now we can substitute the actual values of V1 and V2, as per the information given in the question,
Average speed = 2
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1/90 + 1/60
Average speed = 2
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5/180
Average Speed = 2 x 180/5
Average Speed = 360/5
Average Speed = 72 km/hr.
Therefore the average speed would come out to be 72 Kms/Hr.