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The length of the rectangle is greater than breadth by 3 cm .if the length is increased by 9cm and the breadth is reduced by 5cm ,the area remains the same.find the dimensions of the rectangle?
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The length of the rectangle is greater than breadth by 3 cm .if the le...
Problem Statement
We have a rectangle where the length exceeds the breadth by 3 cm. If the length is increased by 9 cm and the breadth is decreased by 5 cm, the area remains unchanged. We need to find the dimensions of the rectangle.
Let’s Define Variables
- Let the breadth of the rectangle be represented as "b" cm.
- Therefore, the length can be expressed as "l = b + 3" cm.
Original Area
- The original area of the rectangle can be calculated as:
- Area = Length × Breadth
- Area = (b + 3) × b
New Dimensions
- After the changes:
- New Length = (b + 3) + 9 = b + 12 cm
- New Breadth = b - 5 cm
Area After Changes
- The area with new dimensions is:
- New Area = New Length × New Breadth
- New Area = (b + 12) × (b - 5)
Setting Up the Equation
- Since the area remains the same:
- (b + 3) × b = (b + 12) × (b - 5)
Expanding the Equation
- Expanding both sides:
- b^2 + 3b = b^2 + 12b - 5b - 60
Simplifying the Equation
- This reduces to:
- 3b = 7b - 60
- 60 = 4b
- b = 15 cm
Calculating Length
- Now, substituting back to find the length:
- l = b + 3 = 15 + 3 = 18 cm
Final Dimensions
- Therefore, the dimensions of the rectangle are:
- Breadth = 15 cm
- Length = 18 cm
Community Answer
The length of the rectangle is greater than breadth by 3 cm .if the le...
18cm,15cm
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The length of the rectangle is greater than breadth by 3 cm .if the length is increased by 9cm and the breadth is reduced by 5cm ,the area remains the same.find the dimensions of the rectangle?
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