The distance of a point (-5, 6) from the y- axis isa)6 unitsb)5 unitsc...
the distance of the point (-5, 6) from y- axis is |-5| units.
In general, the distance of the point (x,y) from x-axis is y and from y-axis is x.
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The distance of a point (-5, 6) from the y- axis isa)6 unitsb)5 unitsc...
To find the distance of a point from the y-axis, we need to drop a perpendicular from the point to the y-axis. This perpendicular will intersect the y-axis at a point. The distance between the point and the y-axis will be the length of this perpendicular.
Steps to find the distance of point (-5, 6) from the y-axis:
1. Draw a coordinate plane with x-axis and y-axis.
2. Plot the given point (-5, 6) on the coordinate plane.
3. Draw a perpendicular line from the point (-5, 6) to the y-axis.
4. The perpendicular line will intersect the y-axis at a point P.
5. Measure the distance between the point P and the y-axis. This distance is the required answer.
Calculation:
- The x-coordinate of point P will be 0, since it lies on the y-axis.
- The y-coordinate of point P can be found by dropping a perpendicular from the point (-5, 6) to the x-axis. This perpendicular will intersect the x-axis at a point Q.
- The y-coordinate of point Q will be 0, since it lies on the x-axis.
- The distance between points (-5, 6) and (0, 0) can be found using the distance formula: √((-5-0)² + (6-0)²) = √(25+36) = √61.
- The distance between points (0, 0) and point Q can be found using the Pythagorean theorem: PQ² = (-5-0)² + (0-0)² = 25.
- Therefore, the y-coordinate of point P is √25 = 5.
- The distance between the point (-5, 6) and the y-axis is the distance between points (-5, 6) and (0, 5), which can be found using the distance formula: √((-5-0)² + (6-5)²) = √(25+1) = √26.
- Therefore, the distance of the point (-5, 6) from the y-axis is 5 units (Option B).
Hence, the correct answer is option B.
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