The perimeter of a right triangle is 24 cm. If it's hypotenuse is 10 c...
Problem: Find the area of a right triangle whose perimeter is 24 cm and hypotenuse is 10 cm.
Solution:
To solve this problem, we will use the Pythagorean theorem and the formula for the perimeter of a triangle.
Step 1: Determine the lengths of the other two sides of the triangle.
Let's assume that the two legs of the triangle have lengths a and b. Since the hypotenuse is 10 cm, we can use the Pythagorean theorem to find the values of a and b:
a^2 + b^2 = 10^2
a^2 + b^2 = 100
Step 2: Use the formula for the perimeter of a triangle to find the value of a + b.
The formula for the perimeter of a triangle is:
perimeter = a + b + c
where c is the length of the hypotenuse. In this case, we know that the perimeter is 24 cm, and we know that c = 10 cm. So we can substitute these values into the formula and solve for a + b:
24 = a + b + 10
a + b = 14
Step 3: Solve the system of equations to find the values of a and b.
We have two equations:
a^2 + b^2 = 100
a + b = 14
We can use substitution to solve for one of the variables. For example, we can solve for b in terms of a:
b = 14 - a
Then we can substitute this expression for b into the first equation:
a^2 + (14 - a)^2 = 100
Expanding the square and simplifying, we get:
2a^2 - 28a + 96 = 0
Dividing by 2, we get:
a^2 - 14a + 48 = 0
This quadratic equation factors as:
(a - 6)(a - 8) = 0
So the solutions are a = 6 and a = 8. Since a and b are interchangeable, we can also have b = 6 and b = 8.
Step 4: Calculate the area of the triangle.
Now that we know the lengths of the legs of the triangle, we can use the formula for the area of a right triangle:
area = (1/2)ab
Using the values of a and b, we get:
area = (1/2)(6)(8) = 24 cm^2
Therefore, the area of the right triangle is 24 square centimeters.
The perimeter of a right triangle is 24 cm. If it's hypotenuse is 10 c...
Perimeter of the triangle =24 cm,
AB+BC+AC=24,
a+b+10=24,
a+b=14 (1),
From Pythagoras theorem,
AB2+BC2=AC2,
a2+b2=102,
a2+b2=100 (2),
Now,
(a+b)2=a2+b2+2ab,
From (1) and (2),
(14)2=100+2ab,
2ab=196−100,
2ab=96,
ab=48,
Area of the triangle =21×base×height,
=21ab
=248
=24 cm2
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