Let M and N be two 3 x 3 non-singular skew symmetric matrices such tha...
Using the property of transpose, we have:
(MN)T = NTMT
Since MN = NM, we can rewrite the above equation as:
MTNT = NTMT
Multiplying both sides by N on the left, we get:
NTMTN = NTMTN
Since N is non-singular, we can cancel it from both sides to get:
MTN = NTN
Now, let's evaluate M2N2(MTN):
M2N2(MTN) = M2N2(NTMT)
Using the commutative property of matrix multiplication, we can rearrange the order of multiplication:
M2N2(NTMT) = M2(NTMT)N2
Since M and N are skew symmetric matrices, we have:
M2 = -M and N2 = -N
Substituting these values, we get:
M2N2(NTMT) = -M(NTMT)(-N)
Multiplying the matrices, we have:
M2N2(NTMT) = MN(NTMT)N
Since MN = NM, we can write it as:
M2N2(NTMT) = NM(NTMT)N
Using the associativity property of matrix multiplication, we can rearrange the order of multiplication:
M2N2(NTMT) = N(MNT)(NT)N
Using the fact that MNT = MTN, we have:
M2N2(NTMT) = N(MTN)(NT)N
Since MTN = NTN, we can rewrite it as:
M2N2(NTMT) = N(NTMT)(NT)N
Using the fact that (NT)T = N, we have:
M2N2(NTMT) = N(NTMT)NN
Since NN = N2 = -N, we can substitute it in:
M2N2(NTMT) = N(NTMT)(-N)
Multiplying the matrices, we have:
M2N2(NTMT) = NTMTNTN
Using the fact that NTNT = -N2 = N, we have:
M2N2(NTMT) = NTMTNN
Since NN = N2 = -N, we can substitute it in:
M2N2(NTMT) = NTMT(-N)
Multiplying the matrices, we have:
M2N2(NTMT) = -NTMTN
Since NTMTN = -M2N2(MTN), we can substitute it in:
M2N2(NTMT) = -(-M2N2(MTN))
Simplifying the double negative, we get:
M2N2(NTMT) = M2N2(MTN)
Therefore, M2N2(NTMT) is equal to M2N2(MTN).
Let M and N be two 3 x 3 non-singular skew symmetric matrices such tha...