Number of P-O bonds in P4O10 is 12.

Explanation:
P4O10 is a compound formed by the combination of four phosphorus (P) atoms and ten oxygen (O) atoms. In this compound, each phosphorus atom is bonded to three oxygen atoms.

1. Molecular formula of P4O10:
The molecular formula of P4O10 represents that there are four phosphorus atoms and ten oxygen atoms in the compound.

2. Structure of P4O10:
The structure of P4O10 can be represented as follows:
P=O P=O P=O P=O
| | | |
O O O O
| | | |
P=O P=O P=O P=O
| | | |
O O O O

3. Counting the P-O bonds:
In the structure of P4O10, each phosphorus atom is bonded to three oxygen atoms. Therefore, the number of P-O bonds in one molecule of P4O10 can be calculated as follows:

Number of P-O bonds = Number of phosphorus atoms × Number of oxygen atoms bonded to each phosphorus atom

Number of P-O bonds = 4 × 3 = 12

Therefore, there are 12 P-O bonds in one molecule of P4O10.

4. Visualization of P-O bonds:
To visualize the P-O bonds, we can represent them with lines connecting the phosphorus and oxygen atoms in the structure of P4O10:

P=O P=O P=O P=O
| | | |
O O O O
| | | |
P=O P=O P=O P=O
| | | |
O O O O

Each line represents a P-O bond, and there are 12 such lines in the structure.

In conclusion, there are 12 P-O bonds in P4O10, which is derived from the structure of the compound where each phosphorus atom is bonded to three oxygen atoms.