To solve this problem, we need to first understand the concept of a clockwise revolution and how it relates to the hour hand of a clock.

Clockwise revolution: A complete clockwise revolution is when the hour hand of a clock completes a full circle and returns to its starting position, which is 12 o'clock.

Hour hand: The hour hand of a clock represents the hours that have elapsed since the start of the day. It moves at a slower pace than the minute hand, which represents the minutes that have elapsed since the start of the hour.

Now, let's look at the question again. We need to find out what fraction of a clockwise revolution the hour hand of a clock turns through when it goes from 1 to 10. Here's how we can solve this problem:

Step 1: Determine the distance between 1 and 10 on a clock face.

We know that a clock face has 12 hour markers, so the distance between 1 and 10 is 9 hour markers.

Step 2: Calculate the angle between 1 and 10.

To calculate the angle between 1 and 10, we need to know that a full circle has 360 degrees. Since there are 12 hour markers on a clock face, each hour marker represents 30 degrees (360 degrees ÷ 12 hour markers = 30 degrees).

Therefore, the angle between 1 and 10 is:

9 hour markers × 30 degrees per hour marker = 270 degrees

Step 3: Determine what fraction of a clockwise revolution the hour hand turns through.

We know that a full clockwise revolution is 360 degrees, so we need to express 270 degrees as a fraction of 360 degrees.

270 degrees ÷ 360 degrees = 3/4

Therefore, the answer is 3/4, which means that the hour hand turns through 3/4 of a clockwise revolution when it goes from 1 to 10 on a clock face.

When the hour hand goes from 1 to 10. it covers 9 hours. so the fraction of a clockwise revolution would be 9/12 = 3/4