The 1H NMR spectrum of a compound A shows a doublet and a septet. Whic...
Explanation:
The given 1H NMR spectrum of compound A shows a doublet and a septet. Let's analyze each option one by one to find out which one is consistent with the given spectrum.
Option A: The spectrum is consistent with A containing CH3CH2CH2 group.
- A CH3CH2CH2 group would give a quartet, not a doublet or septet.
- Therefore, option A is not correct.
Option B: The spectrum is consistent with A being (CH3)2 CHCl.
- (CH3)2 CHCl has two different types of protons: six equivalent protons on the two methyl groups and one proton on the CHCl group.
- The six equivalent protons would give a septet (n+1 rule, where n=5), and the proton on CHCl group would give a doublet.
- Therefore, option B is correct.
Option C: The spectrum is consistent with A containing a CH3CH2 group.
- A CH3CH2 group would give a quartet, not a doublet or septet.
- Therefore, option C is not correct.
Option D: The spectrum is consistent with A being (CH3)2CCl2.
- (CH3)2CCl2 has two different types of protons: six equivalent protons on the two methyl groups and two equivalent protons on the CCl2 group.
- The six equivalent protons would give a septet (n+1 rule, where n=5), and the two equivalent protons on the CCl2 group would give a triplet (n+1 rule, where n=1).
- Therefore, option D is not correct.
Conclusion:
The correct answer is option B, as the given 1H NMR spectrum is consistent with A being (CH3)2 CHCl.
The 1H NMR spectrum of a compound A shows a doublet and a septet. Whic...
Septet signal mEANS SURROUNDING HYDROGEN ARE 6 DEM MULTIPLICITY IS N+1 DOUBLET SIGNAL MEANS SUROUNDING HYDROGEN IS 1