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rationalise the denominator of 1/√7-3
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rationalise the denominator of 1/√7-3 Related: Additional Question An...
Solution:

To rationalize the denominator of 1/√7-3, we need to eliminate the radical from the denominator. Here are the steps:

Step 1: Rationalize the denominator by multiplying both the numerator and denominator by the conjugate of the denominator.

The conjugate of √7-3 is √7+3. Therefore, we can multiply both the numerator and denominator by √7+3 to eliminate the radical from the denominator.

1/√7-3 * (√7+3)/(√7+3)

Step 2: Simplify the expression.

1/√7-3 * (√7+3)/(√7+3) = (√7+3)/((√7)^2-3^2)

= (√7+3)/(7-9)

= -(√7+3)/2

Therefore, the rationalized form of 1/√7-3 is -(√7+3)/2.
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rationalise the denominator of 1/√7-3 Related: Additional Question Answers- Number System?
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